Integrand size = 32, antiderivative size = 140 \[ \int \frac {c+d x^2+e x^4+f x^6}{x^8 \sqrt {a+b x^2}} \, dx=-\frac {c \sqrt {a+b x^2}}{7 a x^7}+\frac {(6 b c-7 a d) \sqrt {a+b x^2}}{35 a^2 x^5}-\frac {\left (24 b^2 c-28 a b d+35 a^2 e\right ) \sqrt {a+b x^2}}{105 a^3 x^3}+\frac {\left (48 b^3 c-56 a b^2 d+70 a^2 b e-105 a^3 f\right ) \sqrt {a+b x^2}}{105 a^4 x} \]
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Time = 0.13 (sec) , antiderivative size = 140, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.094, Rules used = {1817, 12, 270} \[ \int \frac {c+d x^2+e x^4+f x^6}{x^8 \sqrt {a+b x^2}} \, dx=\frac {\sqrt {a+b x^2} (6 b c-7 a d)}{35 a^2 x^5}-\frac {\sqrt {a+b x^2} \left (35 a^2 e-28 a b d+24 b^2 c\right )}{105 a^3 x^3}+\frac {\sqrt {a+b x^2} \left (-105 a^3 f+70 a^2 b e-56 a b^2 d+48 b^3 c\right )}{105 a^4 x}-\frac {c \sqrt {a+b x^2}}{7 a x^7} \]
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Rule 12
Rule 270
Rule 1817
Rubi steps \begin{align*} \text {integral}& = -\frac {c \sqrt {a+b x^2}}{7 a x^7}-\frac {\int \frac {6 b c-7 a \left (d+e x^2+f x^4\right )}{x^6 \sqrt {a+b x^2}} \, dx}{7 a} \\ & = -\frac {c \sqrt {a+b x^2}}{7 a x^7}+\frac {(6 b c-7 a d) \sqrt {a+b x^2}}{35 a^2 x^5}+\frac {\int \frac {4 b (6 b c-7 a d)-5 a \left (-7 a e-7 a f x^2\right )}{x^4 \sqrt {a+b x^2}} \, dx}{35 a^2} \\ & = -\frac {c \sqrt {a+b x^2}}{7 a x^7}+\frac {(6 b c-7 a d) \sqrt {a+b x^2}}{35 a^2 x^5}-\frac {\left (24 b^2 c-28 a b d+35 a^2 e\right ) \sqrt {a+b x^2}}{105 a^3 x^3}-\frac {\int \frac {2 b \left (24 b^2 c-28 a b d+35 a^2 e\right )-105 a^3 f}{x^2 \sqrt {a+b x^2}} \, dx}{105 a^3} \\ & = -\frac {c \sqrt {a+b x^2}}{7 a x^7}+\frac {(6 b c-7 a d) \sqrt {a+b x^2}}{35 a^2 x^5}-\frac {\left (24 b^2 c-28 a b d+35 a^2 e\right ) \sqrt {a+b x^2}}{105 a^3 x^3}-\frac {\left (48 b^3 c-56 a b^2 d+70 a^2 b e-105 a^3 f\right ) \int \frac {1}{x^2 \sqrt {a+b x^2}} \, dx}{105 a^3} \\ & = -\frac {c \sqrt {a+b x^2}}{7 a x^7}+\frac {(6 b c-7 a d) \sqrt {a+b x^2}}{35 a^2 x^5}-\frac {\left (24 b^2 c-28 a b d+35 a^2 e\right ) \sqrt {a+b x^2}}{105 a^3 x^3}+\frac {\left (48 b^3 c-56 a b^2 d+70 a^2 b e-105 a^3 f\right ) \sqrt {a+b x^2}}{105 a^4 x} \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.74 \[ \int \frac {c+d x^2+e x^4+f x^6}{x^8 \sqrt {a+b x^2}} \, dx=\frac {\sqrt {a+b x^2} \left (48 b^3 c x^6-8 a b^2 x^4 \left (3 c+7 d x^2\right )+2 a^2 b x^2 \left (9 c+14 d x^2+35 e x^4\right )-a^3 \left (15 c+21 d x^2+35 x^4 \left (e+3 f x^2\right )\right )\right )}{105 a^4 x^7} \]
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Time = 3.58 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.66
method | result | size |
pseudoelliptic | \(-\frac {\left (\left (7 f \,x^{6}+\frac {7}{3} e \,x^{4}+\frac {7}{5} d \,x^{2}+c \right ) a^{3}-\frac {6 b \,x^{2} \left (\frac {35}{9} e \,x^{4}+\frac {14}{9} d \,x^{2}+c \right ) a^{2}}{5}+\frac {8 b^{2} \left (\frac {7 d \,x^{2}}{3}+c \right ) x^{4} a}{5}-\frac {16 b^{3} c \,x^{6}}{5}\right ) \sqrt {b \,x^{2}+a}}{7 x^{7} a^{4}}\) | \(92\) |
gosper | \(-\frac {\sqrt {b \,x^{2}+a}\, \left (105 a^{3} f \,x^{6}-70 a^{2} b e \,x^{6}+56 a \,b^{2} d \,x^{6}-48 b^{3} c \,x^{6}+35 a^{3} e \,x^{4}-28 a^{2} b d \,x^{4}+24 a \,b^{2} c \,x^{4}+21 a^{3} d \,x^{2}-18 a^{2} b c \,x^{2}+15 c \,a^{3}\right )}{105 x^{7} a^{4}}\) | \(111\) |
trager | \(-\frac {\sqrt {b \,x^{2}+a}\, \left (105 a^{3} f \,x^{6}-70 a^{2} b e \,x^{6}+56 a \,b^{2} d \,x^{6}-48 b^{3} c \,x^{6}+35 a^{3} e \,x^{4}-28 a^{2} b d \,x^{4}+24 a \,b^{2} c \,x^{4}+21 a^{3} d \,x^{2}-18 a^{2} b c \,x^{2}+15 c \,a^{3}\right )}{105 x^{7} a^{4}}\) | \(111\) |
risch | \(-\frac {\sqrt {b \,x^{2}+a}\, \left (105 a^{3} f \,x^{6}-70 a^{2} b e \,x^{6}+56 a \,b^{2} d \,x^{6}-48 b^{3} c \,x^{6}+35 a^{3} e \,x^{4}-28 a^{2} b d \,x^{4}+24 a \,b^{2} c \,x^{4}+21 a^{3} d \,x^{2}-18 a^{2} b c \,x^{2}+15 c \,a^{3}\right )}{105 x^{7} a^{4}}\) | \(111\) |
default | \(c \left (-\frac {\sqrt {b \,x^{2}+a}}{7 a \,x^{7}}-\frac {6 b \left (-\frac {\sqrt {b \,x^{2}+a}}{5 a \,x^{5}}-\frac {4 b \left (-\frac {\sqrt {b \,x^{2}+a}}{3 a \,x^{3}}+\frac {2 b \sqrt {b \,x^{2}+a}}{3 a^{2} x}\right )}{5 a}\right )}{7 a}\right )+e \left (-\frac {\sqrt {b \,x^{2}+a}}{3 a \,x^{3}}+\frac {2 b \sqrt {b \,x^{2}+a}}{3 a^{2} x}\right )-\frac {f \sqrt {b \,x^{2}+a}}{a x}+d \left (-\frac {\sqrt {b \,x^{2}+a}}{5 a \,x^{5}}-\frac {4 b \left (-\frac {\sqrt {b \,x^{2}+a}}{3 a \,x^{3}}+\frac {2 b \sqrt {b \,x^{2}+a}}{3 a^{2} x}\right )}{5 a}\right )\) | \(206\) |
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Time = 0.31 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.71 \[ \int \frac {c+d x^2+e x^4+f x^6}{x^8 \sqrt {a+b x^2}} \, dx=\frac {{\left ({\left (48 \, b^{3} c - 56 \, a b^{2} d + 70 \, a^{2} b e - 105 \, a^{3} f\right )} x^{6} - {\left (24 \, a b^{2} c - 28 \, a^{2} b d + 35 \, a^{3} e\right )} x^{4} - 15 \, a^{3} c + 3 \, {\left (6 \, a^{2} b c - 7 \, a^{3} d\right )} x^{2}\right )} \sqrt {b x^{2} + a}}{105 \, a^{4} x^{7}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 891 vs. \(2 (136) = 272\).
Time = 2.12 (sec) , antiderivative size = 891, normalized size of antiderivative = 6.36 \[ \int \frac {c+d x^2+e x^4+f x^6}{x^8 \sqrt {a+b x^2}} \, dx=- \frac {5 a^{6} b^{\frac {19}{2}} c \sqrt {\frac {a}{b x^{2}} + 1}}{35 a^{7} b^{9} x^{6} + 105 a^{6} b^{10} x^{8} + 105 a^{5} b^{11} x^{10} + 35 a^{4} b^{12} x^{12}} - \frac {9 a^{5} b^{\frac {21}{2}} c x^{2} \sqrt {\frac {a}{b x^{2}} + 1}}{35 a^{7} b^{9} x^{6} + 105 a^{6} b^{10} x^{8} + 105 a^{5} b^{11} x^{10} + 35 a^{4} b^{12} x^{12}} - \frac {5 a^{4} b^{\frac {23}{2}} c x^{4} \sqrt {\frac {a}{b x^{2}} + 1}}{35 a^{7} b^{9} x^{6} + 105 a^{6} b^{10} x^{8} + 105 a^{5} b^{11} x^{10} + 35 a^{4} b^{12} x^{12}} - \frac {3 a^{4} b^{\frac {9}{2}} d \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} + \frac {5 a^{3} b^{\frac {25}{2}} c x^{6} \sqrt {\frac {a}{b x^{2}} + 1}}{35 a^{7} b^{9} x^{6} + 105 a^{6} b^{10} x^{8} + 105 a^{5} b^{11} x^{10} + 35 a^{4} b^{12} x^{12}} - \frac {2 a^{3} b^{\frac {11}{2}} d x^{2} \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} + \frac {30 a^{2} b^{\frac {27}{2}} c x^{8} \sqrt {\frac {a}{b x^{2}} + 1}}{35 a^{7} b^{9} x^{6} + 105 a^{6} b^{10} x^{8} + 105 a^{5} b^{11} x^{10} + 35 a^{4} b^{12} x^{12}} - \frac {3 a^{2} b^{\frac {13}{2}} d x^{4} \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} + \frac {40 a b^{\frac {29}{2}} c x^{10} \sqrt {\frac {a}{b x^{2}} + 1}}{35 a^{7} b^{9} x^{6} + 105 a^{6} b^{10} x^{8} + 105 a^{5} b^{11} x^{10} + 35 a^{4} b^{12} x^{12}} - \frac {12 a b^{\frac {15}{2}} d x^{6} \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} + \frac {16 b^{\frac {31}{2}} c x^{12} \sqrt {\frac {a}{b x^{2}} + 1}}{35 a^{7} b^{9} x^{6} + 105 a^{6} b^{10} x^{8} + 105 a^{5} b^{11} x^{10} + 35 a^{4} b^{12} x^{12}} - \frac {8 b^{\frac {17}{2}} d x^{8} \sqrt {\frac {a}{b x^{2}} + 1}}{15 a^{5} b^{4} x^{4} + 30 a^{4} b^{5} x^{6} + 15 a^{3} b^{6} x^{8}} - \frac {\sqrt {b} e \sqrt {\frac {a}{b x^{2}} + 1}}{3 a x^{2}} - \frac {\sqrt {b} f \sqrt {\frac {a}{b x^{2}} + 1}}{a} + \frac {2 b^{\frac {3}{2}} e \sqrt {\frac {a}{b x^{2}} + 1}}{3 a^{2}} \]
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Time = 0.20 (sec) , antiderivative size = 193, normalized size of antiderivative = 1.38 \[ \int \frac {c+d x^2+e x^4+f x^6}{x^8 \sqrt {a+b x^2}} \, dx=\frac {16 \, \sqrt {b x^{2} + a} b^{3} c}{35 \, a^{4} x} - \frac {8 \, \sqrt {b x^{2} + a} b^{2} d}{15 \, a^{3} x} + \frac {2 \, \sqrt {b x^{2} + a} b e}{3 \, a^{2} x} - \frac {\sqrt {b x^{2} + a} f}{a x} - \frac {8 \, \sqrt {b x^{2} + a} b^{2} c}{35 \, a^{3} x^{3}} + \frac {4 \, \sqrt {b x^{2} + a} b d}{15 \, a^{2} x^{3}} - \frac {\sqrt {b x^{2} + a} e}{3 \, a x^{3}} + \frac {6 \, \sqrt {b x^{2} + a} b c}{35 \, a^{2} x^{5}} - \frac {\sqrt {b x^{2} + a} d}{5 \, a x^{5}} - \frac {\sqrt {b x^{2} + a} c}{7 \, a x^{7}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 548 vs. \(2 (124) = 248\).
Time = 0.32 (sec) , antiderivative size = 548, normalized size of antiderivative = 3.91 \[ \int \frac {c+d x^2+e x^4+f x^6}{x^8 \sqrt {a+b x^2}} \, dx=\frac {2 \, {\left (105 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{12} \sqrt {b} f + 210 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{10} b^{\frac {3}{2}} e - 630 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{10} a \sqrt {b} f + 560 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{8} b^{\frac {5}{2}} d - 910 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{8} a b^{\frac {3}{2}} e + 1575 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{8} a^{2} \sqrt {b} f + 1680 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{6} b^{\frac {7}{2}} c - 1400 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{6} a b^{\frac {5}{2}} d + 1540 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{6} a^{2} b^{\frac {3}{2}} e - 2100 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{6} a^{3} \sqrt {b} f - 1008 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{4} a b^{\frac {7}{2}} c + 1176 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{4} a^{2} b^{\frac {5}{2}} d - 1260 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{4} a^{3} b^{\frac {3}{2}} e + 1575 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{4} a^{4} \sqrt {b} f + 336 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} a^{2} b^{\frac {7}{2}} c - 392 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} a^{3} b^{\frac {5}{2}} d + 490 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} a^{4} b^{\frac {3}{2}} e - 630 \, {\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} a^{5} \sqrt {b} f - 48 \, a^{3} b^{\frac {7}{2}} c + 56 \, a^{4} b^{\frac {5}{2}} d - 70 \, a^{5} b^{\frac {3}{2}} e + 105 \, a^{6} \sqrt {b} f\right )}}{105 \, {\left ({\left (\sqrt {b} x - \sqrt {b x^{2} + a}\right )}^{2} - a\right )}^{7}} \]
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Time = 6.07 (sec) , antiderivative size = 124, normalized size of antiderivative = 0.89 \[ \int \frac {c+d x^2+e x^4+f x^6}{x^8 \sqrt {a+b x^2}} \, dx=\frac {\sqrt {b\,x^2+a}\,\left (-105\,f\,a^3+70\,e\,a^2\,b-56\,d\,a\,b^2+48\,c\,b^3\right )}{105\,a^4\,x}-\frac {\sqrt {b\,x^2+a}\,\left (7\,a\,d-6\,b\,c\right )}{35\,a^2\,x^5}-\frac {\sqrt {b\,x^2+a}\,\left (35\,e\,a^2-28\,d\,a\,b+24\,c\,b^2\right )}{105\,a^3\,x^3}-\frac {c\,\sqrt {b\,x^2+a}}{7\,a\,x^7} \]
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